编写条件:
编写方法:
网友求助:
解答如下:
cyc5:=CYC(5);
cyc13:=cyc(13);
cyc34:=cyc(34);
cyc0:=MAXCYC;
cyc5>ref(cyc5,1) and cyc13>ref(cyc13,1) and cyc34>ref(cyc34,1) and cyc0>ref(cyc0,1);
cyc13:=cyc(13);
cyc34:=cyc(34);
cyc0:=MAXCYC;
cyc5>ref(cyc5,1) and cyc13>ref(cyc13,1) and cyc34>ref(cyc34,1) and cyc0>ref(cyc0,1);