编写条件:
编写方法:
网友求助:
解答如下:
cond1:=between(close/ref(close,1),1.0975,1.105);
cond2:=hhv(close,天数)/ref(close,天数)>1.20;
cond2:=hhv(close,天数)/ref(close,天数)>1.20;
dynainfo(8)>0 and strfind(stkname,'S',1)=0 and (ref(count(cond1,天数),1)>=数量 or ref(cond2,1)=1);